Basic question about basic adress

Question

Hello; I am just start developing with the 5300 (WIZ830MJ) and STM32F4 µC. I am a little bit confused about these two things: Base Address: Taken from the W5300 dazasheet" "Physical Address of W5300 Reg = Base Address of T.M.S + Address offset of W5300 Reg For convenience, we assume the Base Address(BA) of T.M.S is 0x08000, and BA of the Physical Address of W5300 Register is 0x08000." I have studied some code examples, first I thougt, base address/ address of Mode Register always is 0x08000, but the address in the code example varies. So what do I have to use in case of an STM32F4 Controller as Start address/First Adress:0x00000 or 0x08000 ??? “Taken from Datasheet Manual of W5300” “6.1.1 16 Bit Data Bus Width In case of using a 16bit data bus width, ADDR[9:1] is used and ADDR0 is connected to ground” Question: I defined GPIO Port E as Address Port: How to write a Address to that Port from internal variable value ? Because : Address uses 9 Portlines, Internal Variable, holding the address is uint_16 type (uint_16 W5300Address) for example Do I always have to shift the value of W5300Address like : Output_to_Port_E = W5300Address <<1 ?? Thanks in advance Marc

Coccoliso · Answer

I can only answer for the first request, the base varies depending on the addressing mode you are set. In Direct address mode : COMMON_REG_BASE = 0x8000 SOCKET_REG_BASE = 0x8000 + 0x0200 In Indirect address mode : COMMON_REG_BASE = 0x0000 SOCKET_REG_BASE = 0x0200 … but maybe this piece of code can serve for the second question uint8 IINCHIP_READ(uint16 addr) { #if (__DEF_IINCHIP_ADDRESS_MODE__ == __DEF_IINCHIP_DIRECT_MODE__) return ({*((vuint8*)(addr));}); #else uint8 data; *((vuint8*)IDM_AR) = addr >> 8; *((vuint8*)IDM_AR1) = addr; if(addr &0x01) data = *((vuint8*)IDM_DR1); else data = *((vuint8*)IDM_DR); return data; #endif } void IINCHIP_WRITE(uint16 addr,uint8 data) { #if (__DEF_IINCHIP_ADDRESS_MODE__ == __DEF_IINCHIP_DIRECT_MODE__) *((vuint8*)(addr)) = data; #else *((vuint8*)IDM_AR) = addr >> 8; *((vuint8*)IDM_AR1) = addr; if(addr &0x01) *((vuint8*)IDM_DR1) = data; else *((vuint8*)IDM_DR) = data; #endif } uint16 getMR(void) { return (IINCHIP_READ(MR_) << 8 | IINCHIP_READ(MR)); } void setMR(uint16 val) { *((volatile uint8*)MR_) = val >> 8; *((volatile uint8*)MR) = val & 0xff; } PS: I used the W5300 only in indirect mode.

sajjad kashkouie · Answer

hi… i am using w5300 chip.and i have problem with addressing registers for initialization… i dont understand what the Base Address(BS) is. for example mentioned in datasheet, if BA = 0x8000, the IR Register’s address equals 0x8002. while Address Bus hase only 10 bits.how can we show 0x8002 by 10 bits?